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App\Entity\Entry {#1846
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**For questions about component-level electronic circuits, tools and equipment.**\n
\n
Rules\n
-----\n
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Hello there, This oscillator is a 0V +10v DC oscillator, which after current passes through the capacitor, it produces a -5v +5v AC on the resistor.\n
\n
We’ve all heard that AC removes DC component and let’s AC pass by. I understand the dynamics of this circuit in case the oscillator were operating with AC (capacitive reactance), however this oscillator is DC, the voltage across the capacitor never changes polarity (since the other side of circuit is ground), so what gives? And why the 10V DC is split on half +5 -5 volts after the capacitor? Thank you!
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Show voter details
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edit
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App\Entity\Entry {#1846
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**For questions about component-level electronic circuits, tools and equipment.**\n
\n
Rules\n
-----\n
\n
1: Be nice.\n
\n
2: Be on-topic (eg: *Electronic*, not *electrical*).\n
\n
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Hello there, This oscillator is a 0V +10v DC oscillator, which after current passes through the capacitor, it produces a -5v +5v AC on the resistor.\n
\n
We’ve all heard that AC removes DC component and let’s AC pass by. I understand the dynamics of this circuit in case the oscillator were operating with AC (capacitive reactance), however this oscillator is DC, the voltage across the capacitor never changes polarity (since the other side of circuit is ground), so what gives? And why the 10V DC is split on half +5 -5 volts after the capacitor? Thank you!
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Show voter details
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moderate
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App\Entity\Entry {#1846
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**For questions about component-level electronic circuits, tools and equipment.**\n
\n
Rules\n
-----\n
\n
1: Be nice.\n
\n
2: Be on-topic (eg: *Electronic*, not *electrical*).\n
\n
3: No commercial stuff, buying, selling or valuations.\n
\n
4: Be safe.\n
\n
---
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Hello there, This oscillator is a 0V +10v DC oscillator, which after current passes through the capacitor, it produces a -5v +5v AC on the resistor.\n
\n
We’ve all heard that AC removes DC component and let’s AC pass by. I understand the dynamics of this circuit in case the oscillator were operating with AC (capacitive reactance), however this oscillator is DC, the voltage across the capacitor never changes polarity (since the other side of circuit is ground), so what gives? And why the 10V DC is split on half +5 -5 volts after the capacitor? Thank you!
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Show voter details
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edit
|
App\Entity\Magazine {#289
+icon: Proxies\__CG__\App\Entity\Image {#270 …}
+name: "askelectronics@discuss.tchncs.de"
+title: "askelectronics"
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**For questions about component-level electronic circuits, tools and equipment.**\n
\n
Rules\n
-----\n
\n
1: Be nice.\n
\n
2: Be on-topic (eg: *Electronic*, not *electrical*).\n
\n
3: No commercial stuff, buying, selling or valuations.\n
\n
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\n
---
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Show voter details
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