Security

Token

There is no security token.

Firewall

main Name
Security enabled
Stateless

Configuration

Key Value
provider security.user.provider.concrete.app_user_provider
context main
entry_point App\Security\KbinAuthenticator
user_checker App\Security\UserChecker
access_denied_handler (none)
access_denied_url (none)
authenticators
[
  "two_factor"
  "remember_me"
  "App\Security\KbinAuthenticator"
  "App\Security\FacebookAuthenticator"
  "App\Security\GoogleAuthenticator"
  "App\Security\GithubAuthenticator"
  "App\Security\KeycloakAuthenticator"
]

Listeners

Listener Duration Response
Symfony\Component\Security\Http\Firewall\ChannelListener {#723
  -map: Symfony\Component\Security\Http\AccessMap {#722 …}
  -logger: Monolog\Logger {#783 …}
  -httpPort: 80
  -httpsPort: 443
}
0.00 ms (none)
Symfony\Component\Security\Http\Firewall\ContextListener {#706
  -tokenStorage: Symfony\Component\Security\Core\Authentication\Token\Storage\TokenStorage {#1017 …}
  -sessionKey: "_security_main"
  -logger: Monolog\Logger {#783 …}
  -userProviders: Symfony\Component\DependencyInjection\Argument\RewindableGenerator {#705 …}
  -dispatcher: Symfony\Component\EventDispatcher\Debug\TraceableEventDispatcher {#747 …}
  -registered: false
  -trustResolver: Scheb\TwoFactorBundle\Security\Authentication\AuthenticationTrustResolver {#780 …}
  -sessionTrackerEnabler: Symfony\Component\Security\Core\Authentication\Token\Storage\UsageTrackingTokenStorage::enableUsageTracking(): void {#703 …}
}
112.65 ms (none)
Symfony\Component\Security\Http\Firewall\AuthenticatorManagerListener {#584
  -authenticatorManager: Symfony\Component\Security\Http\Authentication\AuthenticatorManager {#595 …}
}
0.00 ms (none)
Scheb\TwoFactorBundle\Security\Http\Firewall\TwoFactorAccessListener {#582
  -twoFactorFirewallConfig: Scheb\TwoFactorBundle\Security\TwoFactor\TwoFactorFirewallConfig {#842 …}
  -tokenStorage: Symfony\Component\Security\Core\Authentication\Token\Storage\UsageTrackingTokenStorage {#1018 …}
  -twoFactorAccessDecider: Scheb\TwoFactorBundle\Security\Authorization\TwoFactorAccessDecider {#581 …}
}
0.04 ms (none)
Symfony\Component\Security\Http\Firewall\AccessListener {#579
  -tokenStorage: Symfony\Component\Security\Core\Authentication\Token\Storage\UsageTrackingTokenStorage {#1018 …}
  -accessDecisionManager: Symfony\Component\Security\Core\Authorization\TraceableAccessDecisionManager {#937 …}
  -map: Symfony\Component\Security\Http\AccessMap {#722 …}
}
0.00 ms (none)
Symfony\Component\Security\Http\Firewall\LogoutListener {#786
  -tokenStorage: Symfony\Component\Security\Core\Authentication\Token\Storage\UsageTrackingTokenStorage {#1018 …}
  -options: [
    "csrf_parameter" => "_csrf_token"
    "csrf_token_id" => "logout"
    "logout_path" => "app_logout"
  ]
  -httpUtils: Symfony\Component\Security\Http\HttpUtils {#841 …}
  -csrfTokenManager: Symfony\Component\Security\Csrf\CsrfTokenManager {#1015 …}
  -eventDispatcher: Symfony\Component\EventDispatcher\Debug\TraceableEventDispatcher {#747 …}
}
0.00 ms (none)

Authenticators

No authenticators have been recorded. Check previous profiles on your authentication endpoint.

Access Decision

affirmative Strategy
# Voter class
1
"Symfony\Component\Security\Core\Authorization\Voter\AuthenticatedVoter"
2
"Scheb\TwoFactorBundle\Security\Authorization\Voter\TwoFactorInProgressVoter"
3
"Symfony\Component\Security\Core\Authorization\Voter\RoleHierarchyVoter"
4
"Symfony\Component\Security\Core\Authorization\Voter\ExpressionVoter"
5
"App\Security\Voter\EntryCommentVoter"
6
"App\Security\Voter\EntryVoter"
7
"App\Security\Voter\MagazineVoter"
8
"App\Security\Voter\MessageThreadVoter"
9
"App\Security\Voter\MessageVoter"
10
"App\Security\Voter\NotificationVoter"
11
"App\Security\Voter\OAuth2UserConsentVoter"
12
"App\Security\Voter\PostCommentVoter"
13
"App\Security\Voter\PostVoter"
14
"App\Security\Voter\UserVoter"

Access decision log

# Result Attributes Object
1 DENIED ROLE_USER
null
"Scheb\TwoFactorBundle\Security\Authorization\Voter\TwoFactorInProgressVoter"
ACCESS ABSTAIN
"Symfony\Component\Security\Core\Authorization\Voter\RoleHierarchyVoter"
ACCESS DENIED
"App\Security\Voter\EntryCommentVoter"
ACCESS ABSTAIN
"App\Security\Voter\EntryVoter"
ACCESS ABSTAIN
"App\Security\Voter\MagazineVoter"
ACCESS ABSTAIN
"App\Security\Voter\MessageThreadVoter"
ACCESS ABSTAIN
"App\Security\Voter\MessageVoter"
ACCESS ABSTAIN
"App\Security\Voter\NotificationVoter"
ACCESS ABSTAIN
"App\Security\Voter\OAuth2UserConsentVoter"
ACCESS ABSTAIN
"App\Security\Voter\PostCommentVoter"
ACCESS ABSTAIN
"App\Security\Voter\PostVoter"
ACCESS ABSTAIN
"App\Security\Voter\UserVoter"
ACCESS ABSTAIN
Show voter details
2 DENIED moderate
App\Entity\Entry {#2419
  +user: Proxies\__CG__\App\Entity\User {#1970 …}
  +magazine: App\Entity\Magazine {#265
    +icon: Proxies\__CG__\App\Entity\Image {#246 …}
    +name: "askelectronics@discuss.tchncs.de"
    +title: "askelectronics"
    +description: """
      **For questions about component-level electronic circuits, tools and equipment.**\n
      \n
      Rules\n
      -----\n
      \n
      1: Be nice.\n
      \n
      2: Be on-topic (eg: *Electronic*, not *electrical*).\n
      \n
      3: No commercial stuff, buying, selling or valuations.\n
      \n
      4: Be safe.\n
      \n
      ---
      """
    +rules: null
    +subscriptionsCount: 1
    +entryCount: 154
    +entryCommentCount: 1230
    +postCount: 1
    +postCommentCount: 4
    +isAdult: false
    +customCss: null
    +lastActive: DateTime @1729413608 {#275
      date: 2024-10-20 10:40:08.0 +02:00
    }
    +markedForDeletionAt: null
    +tags: null
    +moderators: Doctrine\ORM\PersistentCollection {#237 …}
    +ownershipRequests: Doctrine\ORM\PersistentCollection {#233 …}
    +moderatorRequests: Doctrine\ORM\PersistentCollection {#222 …}
    +entries: Doctrine\ORM\PersistentCollection {#180 …}
    +posts: Doctrine\ORM\PersistentCollection {#138 …}
    +subscriptions: Doctrine\ORM\PersistentCollection {#200 …}
    +bans: Doctrine\ORM\PersistentCollection {#117 …}
    +reports: Doctrine\ORM\PersistentCollection {#103 …}
    +badges: Doctrine\ORM\PersistentCollection {#81 …}
    +logs: Doctrine\ORM\PersistentCollection {#71 …}
    +awards: Doctrine\ORM\PersistentCollection {#1346 …}
    +categories: Doctrine\ORM\PersistentCollection {#1823 …}
    -id: 11
    +apId: "askelectronics@discuss.tchncs.de"
    +apProfileId: "https://discuss.tchncs.de/c/askelectronics"
    +apPublicUrl: "https://discuss.tchncs.de/c/askelectronics"
    +apFollowersUrl: "https://discuss.tchncs.de/c/askelectronics/followers"
    +apInboxUrl: "https://discuss.tchncs.de/inbox"
    +apDomain: "discuss.tchncs.de"
    +apPreferredUsername: "askelectronics"
    +apDiscoverable: true
    +apManuallyApprovesFollowers: null
    +privateKey: null
    +publicKey: null
    +apFetchedAt: DateTime @1727247714 {#269
      date: 2024-09-25 09:01:54.0 +02:00
    }
    +apDeletedAt: null
    +apTimeoutAt: null
    +visibility: "visible             "
    +createdAt: DateTimeImmutable @1687144409 {#271
      date: 2023-06-19 05:13:29.0 +02:00
    }
  }
  +image: null
  +domain: Proxies\__CG__\App\Entity\Domain {#1915 …}
  +slug: "What-s-a-simplest-way-to-get-5v-from-12v"
  +title: "What's a simplest way to get -5v from +/-12v?"
  +url: null
  +body: """
    Hi! I'm working on an arduino project that has a -12v/0v/+12 psu. +12 is fed directly into arduinos voltage regulator, so there's also a +5v line available. I need to convert a -5v+5v signal to 0v+5v to feed it into arduinos analogue input and I've already mocked up a schematic in circuitjs based on an opamp that seems to do what I want. The only problem is that it needs -5v to shift the signal to be unipolar. I know that I can invert +5v using another opamp, but maybe there's some simpler way? I'd really like to avoid adding another opamp just for this? In this schematic I used simple voltage divider to get the needed voltage, but I guess that's not the best approach?\n
    \n
    TLDR: I have -12v, 0v, +12v and +5v, what's the easiest way to get -5v?
    """
  +type: "article"
  +lang: "en"
  +isOc: false
  +hasEmbed: false
  +commentCount: 10
  +favouriteCount: 11
  +score: 0
  +isAdult: false
  +sticky: false
  +lastActive: DateTime @1688977313 {#2414
    date: 2023-07-10 10:21:53.0 +02:00
  }
  +ip: null
  +adaAmount: 0
  +tags: null
  +mentions: null
  +comments: Doctrine\ORM\PersistentCollection {#1884 …}
  +votes: Doctrine\ORM\PersistentCollection {#1973 …}
  +reports: Doctrine\ORM\PersistentCollection {#1959 …}
  +favourites: Doctrine\ORM\PersistentCollection {#1927 …}
  +notifications: Doctrine\ORM\PersistentCollection {#2442 …}
  +badges: Doctrine\ORM\PersistentCollection {#2440 …}
  +children: []
  -id: 925
  -titleTs: "'-12':11 '-5':8 'get':7 'simplest':4 'v':9,12 'way':5"
  -bodyTs: "'+12':14,16,149 '+5':29,40,45,97,152 '-12':12,146 '-5':38,82,161 '0v':44,148 'ad':115 'alreadi':57 'also':27 'analogu':52 'anoth':100,116 'approach':142 'arduino':7,21,51 'avail':32 'avoid':114 'base':64 'best':141 'circuitj':63 'convert':36 'd':110 'direct':19 'divid':128 'easiest':157 'fed':18 'feed':48 'get':130,160 'guess':136 'hi':1 'input':53 'invert':96 'know':92 'like':112 'line':31 'm':3 'mayb':103 'mock':58 'need':34,81,132 'opamp':67,101,117 'problem':77 'project':8 'psu':15 'realli':111 'regul':23 'schemat':61,123 'seem':69 'shift':85 'signal':42,87 'simpl':126 'simpler':107 'tldr':143 'unipolar':90 'use':99,125 'v':30,39,41,46,83,98,147,150,153,162 'v/0v':13 've':56 'voltag':22,127,133 'want':74 'way':108,158 'work':4"
  +cross: false
  +upVotes: 0
  +downVotes: 0
  +ranking: 1688806732
  +visibility: "visible             "
  +apId: "https://kbin.social/m/askelectronics@discuss.tchncs.de/t/154276"
  +editedAt: null
  +createdAt: DateTimeImmutable @1688759232 {#1793
    date: 2023-07-07 21:47:12.0 +02:00
  }
}
"Scheb\TwoFactorBundle\Security\Authorization\Voter\TwoFactorInProgressVoter"
ACCESS ABSTAIN
"App\Security\Voter\EntryCommentVoter"
ACCESS ABSTAIN
"App\Security\Voter\EntryVoter"
ACCESS DENIED
"App\Security\Voter\MagazineVoter"
ACCESS ABSTAIN
"App\Security\Voter\MessageThreadVoter"
ACCESS ABSTAIN
"App\Security\Voter\MessageVoter"
ACCESS ABSTAIN
"App\Security\Voter\NotificationVoter"
ACCESS ABSTAIN
"App\Security\Voter\OAuth2UserConsentVoter"
ACCESS ABSTAIN
"App\Security\Voter\PostCommentVoter"
ACCESS ABSTAIN
"App\Security\Voter\PostVoter"
ACCESS ABSTAIN
"App\Security\Voter\UserVoter"
ACCESS ABSTAIN
Show voter details
3 DENIED edit
App\Entity\Entry {#2419
  +user: Proxies\__CG__\App\Entity\User {#1970 …}
  +magazine: App\Entity\Magazine {#265
    +icon: Proxies\__CG__\App\Entity\Image {#246 …}
    +name: "askelectronics@discuss.tchncs.de"
    +title: "askelectronics"
    +description: """
      **For questions about component-level electronic circuits, tools and equipment.**\n
      \n
      Rules\n
      -----\n
      \n
      1: Be nice.\n
      \n
      2: Be on-topic (eg: *Electronic*, not *electrical*).\n
      \n
      3: No commercial stuff, buying, selling or valuations.\n
      \n
      4: Be safe.\n
      \n
      ---
      """
    +rules: null
    +subscriptionsCount: 1
    +entryCount: 154
    +entryCommentCount: 1230
    +postCount: 1
    +postCommentCount: 4
    +isAdult: false
    +customCss: null
    +lastActive: DateTime @1729413608 {#275
      date: 2024-10-20 10:40:08.0 +02:00
    }
    +markedForDeletionAt: null
    +tags: null
    +moderators: Doctrine\ORM\PersistentCollection {#237 …}
    +ownershipRequests: Doctrine\ORM\PersistentCollection {#233 …}
    +moderatorRequests: Doctrine\ORM\PersistentCollection {#222 …}
    +entries: Doctrine\ORM\PersistentCollection {#180 …}
    +posts: Doctrine\ORM\PersistentCollection {#138 …}
    +subscriptions: Doctrine\ORM\PersistentCollection {#200 …}
    +bans: Doctrine\ORM\PersistentCollection {#117 …}
    +reports: Doctrine\ORM\PersistentCollection {#103 …}
    +badges: Doctrine\ORM\PersistentCollection {#81 …}
    +logs: Doctrine\ORM\PersistentCollection {#71 …}
    +awards: Doctrine\ORM\PersistentCollection {#1346 …}
    +categories: Doctrine\ORM\PersistentCollection {#1823 …}
    -id: 11
    +apId: "askelectronics@discuss.tchncs.de"
    +apProfileId: "https://discuss.tchncs.de/c/askelectronics"
    +apPublicUrl: "https://discuss.tchncs.de/c/askelectronics"
    +apFollowersUrl: "https://discuss.tchncs.de/c/askelectronics/followers"
    +apInboxUrl: "https://discuss.tchncs.de/inbox"
    +apDomain: "discuss.tchncs.de"
    +apPreferredUsername: "askelectronics"
    +apDiscoverable: true
    +apManuallyApprovesFollowers: null
    +privateKey: null
    +publicKey: null
    +apFetchedAt: DateTime @1727247714 {#269
      date: 2024-09-25 09:01:54.0 +02:00
    }
    +apDeletedAt: null
    +apTimeoutAt: null
    +visibility: "visible             "
    +createdAt: DateTimeImmutable @1687144409 {#271
      date: 2023-06-19 05:13:29.0 +02:00
    }
  }
  +image: null
  +domain: Proxies\__CG__\App\Entity\Domain {#1915 …}
  +slug: "What-s-a-simplest-way-to-get-5v-from-12v"
  +title: "What's a simplest way to get -5v from +/-12v?"
  +url: null
  +body: """
    Hi! I'm working on an arduino project that has a -12v/0v/+12 psu. +12 is fed directly into arduinos voltage regulator, so there's also a +5v line available. I need to convert a -5v+5v signal to 0v+5v to feed it into arduinos analogue input and I've already mocked up a schematic in circuitjs based on an opamp that seems to do what I want. The only problem is that it needs -5v to shift the signal to be unipolar. I know that I can invert +5v using another opamp, but maybe there's some simpler way? I'd really like to avoid adding another opamp just for this? In this schematic I used simple voltage divider to get the needed voltage, but I guess that's not the best approach?\n
    \n
    TLDR: I have -12v, 0v, +12v and +5v, what's the easiest way to get -5v?
    """
  +type: "article"
  +lang: "en"
  +isOc: false
  +hasEmbed: false
  +commentCount: 10
  +favouriteCount: 11
  +score: 0
  +isAdult: false
  +sticky: false
  +lastActive: DateTime @1688977313 {#2414
    date: 2023-07-10 10:21:53.0 +02:00
  }
  +ip: null
  +adaAmount: 0
  +tags: null
  +mentions: null
  +comments: Doctrine\ORM\PersistentCollection {#1884 …}
  +votes: Doctrine\ORM\PersistentCollection {#1973 …}
  +reports: Doctrine\ORM\PersistentCollection {#1959 …}
  +favourites: Doctrine\ORM\PersistentCollection {#1927 …}
  +notifications: Doctrine\ORM\PersistentCollection {#2442 …}
  +badges: Doctrine\ORM\PersistentCollection {#2440 …}
  +children: []
  -id: 925
  -titleTs: "'-12':11 '-5':8 'get':7 'simplest':4 'v':9,12 'way':5"
  -bodyTs: "'+12':14,16,149 '+5':29,40,45,97,152 '-12':12,146 '-5':38,82,161 '0v':44,148 'ad':115 'alreadi':57 'also':27 'analogu':52 'anoth':100,116 'approach':142 'arduino':7,21,51 'avail':32 'avoid':114 'base':64 'best':141 'circuitj':63 'convert':36 'd':110 'direct':19 'divid':128 'easiest':157 'fed':18 'feed':48 'get':130,160 'guess':136 'hi':1 'input':53 'invert':96 'know':92 'like':112 'line':31 'm':3 'mayb':103 'mock':58 'need':34,81,132 'opamp':67,101,117 'problem':77 'project':8 'psu':15 'realli':111 'regul':23 'schemat':61,123 'seem':69 'shift':85 'signal':42,87 'simpl':126 'simpler':107 'tldr':143 'unipolar':90 'use':99,125 'v':30,39,41,46,83,98,147,150,153,162 'v/0v':13 've':56 'voltag':22,127,133 'want':74 'way':108,158 'work':4"
  +cross: false
  +upVotes: 0
  +downVotes: 0
  +ranking: 1688806732
  +visibility: "visible             "
  +apId: "https://kbin.social/m/askelectronics@discuss.tchncs.de/t/154276"
  +editedAt: null
  +createdAt: DateTimeImmutable @1688759232 {#1793
    date: 2023-07-07 21:47:12.0 +02:00
  }
}
"Scheb\TwoFactorBundle\Security\Authorization\Voter\TwoFactorInProgressVoter"
ACCESS ABSTAIN
"App\Security\Voter\EntryCommentVoter"
ACCESS ABSTAIN
"App\Security\Voter\EntryVoter"
ACCESS DENIED
"App\Security\Voter\MagazineVoter"
ACCESS ABSTAIN
"App\Security\Voter\MessageThreadVoter"
ACCESS ABSTAIN
"App\Security\Voter\MessageVoter"
ACCESS ABSTAIN
"App\Security\Voter\NotificationVoter"
ACCESS ABSTAIN
"App\Security\Voter\OAuth2UserConsentVoter"
ACCESS ABSTAIN
"App\Security\Voter\PostCommentVoter"
ACCESS ABSTAIN
"App\Security\Voter\PostVoter"
ACCESS ABSTAIN
"App\Security\Voter\UserVoter"
ACCESS ABSTAIN
Show voter details
4 DENIED moderate
App\Entity\Entry {#2419
  +user: Proxies\__CG__\App\Entity\User {#1970 …}
  +magazine: App\Entity\Magazine {#265
    +icon: Proxies\__CG__\App\Entity\Image {#246 …}
    +name: "askelectronics@discuss.tchncs.de"
    +title: "askelectronics"
    +description: """
      **For questions about component-level electronic circuits, tools and equipment.**\n
      \n
      Rules\n
      -----\n
      \n
      1: Be nice.\n
      \n
      2: Be on-topic (eg: *Electronic*, not *electrical*).\n
      \n
      3: No commercial stuff, buying, selling or valuations.\n
      \n
      4: Be safe.\n
      \n
      ---
      """
    +rules: null
    +subscriptionsCount: 1
    +entryCount: 154
    +entryCommentCount: 1230
    +postCount: 1
    +postCommentCount: 4
    +isAdult: false
    +customCss: null
    +lastActive: DateTime @1729413608 {#275
      date: 2024-10-20 10:40:08.0 +02:00
    }
    +markedForDeletionAt: null
    +tags: null
    +moderators: Doctrine\ORM\PersistentCollection {#237 …}
    +ownershipRequests: Doctrine\ORM\PersistentCollection {#233 …}
    +moderatorRequests: Doctrine\ORM\PersistentCollection {#222 …}
    +entries: Doctrine\ORM\PersistentCollection {#180 …}
    +posts: Doctrine\ORM\PersistentCollection {#138 …}
    +subscriptions: Doctrine\ORM\PersistentCollection {#200 …}
    +bans: Doctrine\ORM\PersistentCollection {#117 …}
    +reports: Doctrine\ORM\PersistentCollection {#103 …}
    +badges: Doctrine\ORM\PersistentCollection {#81 …}
    +logs: Doctrine\ORM\PersistentCollection {#71 …}
    +awards: Doctrine\ORM\PersistentCollection {#1346 …}
    +categories: Doctrine\ORM\PersistentCollection {#1823 …}
    -id: 11
    +apId: "askelectronics@discuss.tchncs.de"
    +apProfileId: "https://discuss.tchncs.de/c/askelectronics"
    +apPublicUrl: "https://discuss.tchncs.de/c/askelectronics"
    +apFollowersUrl: "https://discuss.tchncs.de/c/askelectronics/followers"
    +apInboxUrl: "https://discuss.tchncs.de/inbox"
    +apDomain: "discuss.tchncs.de"
    +apPreferredUsername: "askelectronics"
    +apDiscoverable: true
    +apManuallyApprovesFollowers: null
    +privateKey: null
    +publicKey: null
    +apFetchedAt: DateTime @1727247714 {#269
      date: 2024-09-25 09:01:54.0 +02:00
    }
    +apDeletedAt: null
    +apTimeoutAt: null
    +visibility: "visible             "
    +createdAt: DateTimeImmutable @1687144409 {#271
      date: 2023-06-19 05:13:29.0 +02:00
    }
  }
  +image: null
  +domain: Proxies\__CG__\App\Entity\Domain {#1915 …}
  +slug: "What-s-a-simplest-way-to-get-5v-from-12v"
  +title: "What's a simplest way to get -5v from +/-12v?"
  +url: null
  +body: """
    Hi! I'm working on an arduino project that has a -12v/0v/+12 psu. +12 is fed directly into arduinos voltage regulator, so there's also a +5v line available. I need to convert a -5v+5v signal to 0v+5v to feed it into arduinos analogue input and I've already mocked up a schematic in circuitjs based on an opamp that seems to do what I want. The only problem is that it needs -5v to shift the signal to be unipolar. I know that I can invert +5v using another opamp, but maybe there's some simpler way? I'd really like to avoid adding another opamp just for this? In this schematic I used simple voltage divider to get the needed voltage, but I guess that's not the best approach?\n
    \n
    TLDR: I have -12v, 0v, +12v and +5v, what's the easiest way to get -5v?
    """
  +type: "article"
  +lang: "en"
  +isOc: false
  +hasEmbed: false
  +commentCount: 10
  +favouriteCount: 11
  +score: 0
  +isAdult: false
  +sticky: false
  +lastActive: DateTime @1688977313 {#2414
    date: 2023-07-10 10:21:53.0 +02:00
  }
  +ip: null
  +adaAmount: 0
  +tags: null
  +mentions: null
  +comments: Doctrine\ORM\PersistentCollection {#1884 …}
  +votes: Doctrine\ORM\PersistentCollection {#1973 …}
  +reports: Doctrine\ORM\PersistentCollection {#1959 …}
  +favourites: Doctrine\ORM\PersistentCollection {#1927 …}
  +notifications: Doctrine\ORM\PersistentCollection {#2442 …}
  +badges: Doctrine\ORM\PersistentCollection {#2440 …}
  +children: []
  -id: 925
  -titleTs: "'-12':11 '-5':8 'get':7 'simplest':4 'v':9,12 'way':5"
  -bodyTs: "'+12':14,16,149 '+5':29,40,45,97,152 '-12':12,146 '-5':38,82,161 '0v':44,148 'ad':115 'alreadi':57 'also':27 'analogu':52 'anoth':100,116 'approach':142 'arduino':7,21,51 'avail':32 'avoid':114 'base':64 'best':141 'circuitj':63 'convert':36 'd':110 'direct':19 'divid':128 'easiest':157 'fed':18 'feed':48 'get':130,160 'guess':136 'hi':1 'input':53 'invert':96 'know':92 'like':112 'line':31 'm':3 'mayb':103 'mock':58 'need':34,81,132 'opamp':67,101,117 'problem':77 'project':8 'psu':15 'realli':111 'regul':23 'schemat':61,123 'seem':69 'shift':85 'signal':42,87 'simpl':126 'simpler':107 'tldr':143 'unipolar':90 'use':99,125 'v':30,39,41,46,83,98,147,150,153,162 'v/0v':13 've':56 'voltag':22,127,133 'want':74 'way':108,158 'work':4"
  +cross: false
  +upVotes: 0
  +downVotes: 0
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      Hi! I'm working on an arduino project that has a -12v/0v/+12 psu. +12 is fed directly into arduinos voltage regulator, so there's also a +5v line available. I need to convert a -5v+5v signal to 0v+5v to feed it into arduinos analogue input and I've already mocked up a schematic in circuitjs based on an opamp that seems to do what I want. The only problem is that it needs -5v to shift the signal to be unipolar. I know that I can invert +5v using another opamp, but maybe there's some simpler way? I'd really like to avoid adding another opamp just for this? In this schematic I used simple voltage divider to get the needed voltage, but I guess that's not the best approach?\n
      \n
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      \n
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      Hi! I'm working on an arduino project that has a -12v/0v/+12 psu. +12 is fed directly into arduinos voltage regulator, so there's also a +5v line available. I need to convert a -5v+5v signal to 0v+5v to feed it into arduinos analogue input and I've already mocked up a schematic in circuitjs based on an opamp that seems to do what I want. The only problem is that it needs -5v to shift the signal to be unipolar. I know that I can invert +5v using another opamp, but maybe there's some simpler way? I'd really like to avoid adding another opamp just for this? In this schematic I used simple voltage divider to get the needed voltage, but I guess that's not the best approach?\n
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      TLDR: I have -12v, 0v, +12v and +5v, what's the easiest way to get -5v?
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        +body: "Supply the OpAmp with +/-12V or +5/0V and use a non inverting Summing OpAmp Circuit to get your 0-5V signal. V1 is 5V, V2 your input."
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      +body: "thanks! gonna give it a try tomorrow. I'm pretty new to this, and never used opAmps in non-inverting configuration, so I missed this option"
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    +body: "Exiting! It has been some time for me too, let me know how you solved the problem at the end."
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    it worked! (at least in the sim)  \n
     thanks a lot!  \n
     I'm not sure I got all the math right, since I get 0 - 5.05V on the output, but it's not a deal breaker for me.  \n
     I attached the schematics, but not sure that images in comments federate from kbin to lemmy, so if you don't see it, try opening an original link to this comment.
    """
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      Hi! I'm working on an arduino project that has a -12v/0v/+12 psu. +12 is fed directly into arduinos voltage regulator, so there's also a +5v line available. I need to convert a -5v+5v signal to 0v+5v to feed it into arduinos analogue input and I've already mocked up a schematic in circuitjs based on an opamp that seems to do what I want. The only problem is that it needs -5v to shift the signal to be unipolar. I know that I can invert +5v using another opamp, but maybe there's some simpler way? I'd really like to avoid adding another opamp just for this? In this schematic I used simple voltage divider to get the needed voltage, but I guess that's not the best approach?\n
      \n
      TLDR: I have -12v, 0v, +12v and +5v, what's the easiest way to get -5v?
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    it worked! (at least in the sim)  \n
     thanks a lot!  \n
     I'm not sure I got all the math right, since I get 0 - 5.05V on the output, but it's not a deal breaker for me.  \n
     I attached the schematics, but not sure that images in comments federate from kbin to lemmy, so if you don't see it, try opening an original link to this comment.
    """
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      Hi! I'm working on an arduino project that has a -12v/0v/+12 psu. +12 is fed directly into arduinos voltage regulator, so there's also a +5v line available. I need to convert a -5v+5v signal to 0v+5v to feed it into arduinos analogue input and I've already mocked up a schematic in circuitjs based on an opamp that seems to do what I want. The only problem is that it needs -5v to shift the signal to be unipolar. I know that I can invert +5v using another opamp, but maybe there's some simpler way? I'd really like to avoid adding another opamp just for this? In this schematic I used simple voltage divider to get the needed voltage, but I guess that's not the best approach?\n
      \n
      TLDR: I have -12v, 0v, +12v and +5v, what's the easiest way to get -5v?
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        +body: "Supply the OpAmp with +/-12V or +5/0V and use a non inverting Summing OpAmp Circuit to get your 0-5V signal. V1 is 5V, V2 your input."
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    it worked! (at least in the sim)  \n
     thanks a lot!  \n
     I'm not sure I got all the math right, since I get 0 - 5.05V on the output, but it's not a deal breaker for me.  \n
     I attached the schematics, but not sure that images in comments federate from kbin to lemmy, so if you don't see it, try opening an original link to this comment.
    """
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    +slug: "What-s-a-simplest-way-to-get-5v-from-12v"
    +title: "What's a simplest way to get -5v from +/-12v?"
    +url: null
    +body: """
      Hi! I'm working on an arduino project that has a -12v/0v/+12 psu. +12 is fed directly into arduinos voltage regulator, so there's also a +5v line available. I need to convert a -5v+5v signal to 0v+5v to feed it into arduinos analogue input and I've already mocked up a schematic in circuitjs based on an opamp that seems to do what I want. The only problem is that it needs -5v to shift the signal to be unipolar. I know that I can invert +5v using another opamp, but maybe there's some simpler way? I'd really like to avoid adding another opamp just for this? In this schematic I used simple voltage divider to get the needed voltage, but I guess that's not the best approach?\n
      \n
      TLDR: I have -12v, 0v, +12v and +5v, what's the easiest way to get -5v?
      """
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          +body: "Supply the OpAmp with +/-12V or +5/0V and use a non inverting Summing OpAmp Circuit to get your 0-5V signal. V1 is 5V, V2 your input."
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        +body: "thanks! gonna give it a try tomorrow. I'm pretty new to this, and never used opAmps in non-inverting configuration, so I missed this option"
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      +body: "Exiting! It has been some time for me too, let me know how you solved the problem at the end."
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    +body: """
      it worked! (at least in the sim)  \n
       thanks a lot!  \n
       I'm not sure I got all the math right, since I get 0 - 5.05V on the output, but it's not a deal breaker for me.  \n
       I attached the schematics, but not sure that images in comments federate from kbin to lemmy, so if you don't see it, try opening an original link to this comment.
      """
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  +body: "ah, a little bit of thinking helped me realize that I don't need 1k in inverting loop and then I'll get 5v instead of 5.05v :) and 100k can also be replaced by 1k"
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      Hi! I'm working on an arduino project that has a -12v/0v/+12 psu. +12 is fed directly into arduinos voltage regulator, so there's also a +5v line available. I need to convert a -5v+5v signal to 0v+5v to feed it into arduinos analogue input and I've already mocked up a schematic in circuitjs based on an opamp that seems to do what I want. The only problem is that it needs -5v to shift the signal to be unipolar. I know that I can invert +5v using another opamp, but maybe there's some simpler way? I'd really like to avoid adding another opamp just for this? In this schematic I used simple voltage divider to get the needed voltage, but I guess that's not the best approach?\n
      \n
      TLDR: I have -12v, 0v, +12v and +5v, what's the easiest way to get -5v?
      """
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          +body: "Supply the OpAmp with +/-12V or +5/0V and use a non inverting Summing OpAmp Circuit to get your 0-5V signal. V1 is 5V, V2 your input."
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      it worked! (at least in the sim)  \n
       thanks a lot!  \n
       I'm not sure I got all the math right, since I get 0 - 5.05V on the output, but it's not a deal breaker for me.  \n
       I attached the schematics, but not sure that images in comments federate from kbin to lemmy, so if you don't see it, try opening an original link to this comment.
      """
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      Hi! I'm working on an arduino project that has a -12v/0v/+12 psu. +12 is fed directly into arduinos voltage regulator, so there's also a +5v line available. I need to convert a -5v+5v signal to 0v+5v to feed it into arduinos analogue input and I've already mocked up a schematic in circuitjs based on an opamp that seems to do what I want. The only problem is that it needs -5v to shift the signal to be unipolar. I know that I can invert +5v using another opamp, but maybe there's some simpler way? I'd really like to avoid adding another opamp just for this? In this schematic I used simple voltage divider to get the needed voltage, but I guess that's not the best approach?\n
      \n
      TLDR: I have -12v, 0v, +12v and +5v, what's the easiest way to get -5v?
      """
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          +body: "Supply the OpAmp with +/-12V or +5/0V and use a non inverting Summing OpAmp Circuit to get your 0-5V signal. V1 is 5V, V2 your input."
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        +body: "thanks! gonna give it a try tomorrow. I'm pretty new to this, and never used opAmps in non-inverting configuration, so I missed this option"
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      it worked! (at least in the sim)  \n
       thanks a lot!  \n
       I'm not sure I got all the math right, since I get 0 - 5.05V on the output, but it's not a deal breaker for me.  \n
       I attached the schematics, but not sure that images in comments federate from kbin to lemmy, so if you don't see it, try opening an original link to this comment.
      """
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      Hi! I'm working on an arduino project that has a -12v/0v/+12 psu. +12 is fed directly into arduinos voltage regulator, so there's also a +5v line available. I need to convert a -5v+5v signal to 0v+5v to feed it into arduinos analogue input and I've already mocked up a schematic in circuitjs based on an opamp that seems to do what I want. The only problem is that it needs -5v to shift the signal to be unipolar. I know that I can invert +5v using another opamp, but maybe there's some simpler way? I'd really like to avoid adding another opamp just for this? In this schematic I used simple voltage divider to get the needed voltage, but I guess that's not the best approach?\n
      \n
      TLDR: I have -12v, 0v, +12v and +5v, what's the easiest way to get -5v?
      """
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            +body: "Supply the OpAmp with +/-12V or +5/0V and use a non inverting Summing OpAmp Circuit to get your 0-5V signal. V1 is 5V, V2 your input."
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          +body: "thanks! gonna give it a try tomorrow. I'm pretty new to this, and never used opAmps in non-inverting configuration, so I missed this option"
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        +body: "Exiting! It has been some time for me too, let me know how you solved the problem at the end."
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      +body: """
        it worked! (at least in the sim)  \n
         thanks a lot!  \n
         I'm not sure I got all the math right, since I get 0 - 5.05V on the output, but it's not a deal breaker for me.  \n
         I attached the schematics, but not sure that images in comments federate from kbin to lemmy, so if you don't see it, try opening an original link to this comment.
        """
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    +body: "ah, a little bit of thinking helped me realize that I don't need 1k in inverting loop and then I'll get 5v instead of 5.05v :) and 100k can also be replaced by 1k"
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  +body: """
    So what should happen if you replace the 1k in the inverting loop by 0 Ohm is, you should get a 5V square wave.\n
    \n
    Is that correct?
    """
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      Hi! I'm working on an arduino project that has a -12v/0v/+12 psu. +12 is fed directly into arduinos voltage regulator, so there's also a +5v line available. I need to convert a -5v+5v signal to 0v+5v to feed it into arduinos analogue input and I've already mocked up a schematic in circuitjs based on an opamp that seems to do what I want. The only problem is that it needs -5v to shift the signal to be unipolar. I know that I can invert +5v using another opamp, but maybe there's some simpler way? I'd really like to avoid adding another opamp just for this? In this schematic I used simple voltage divider to get the needed voltage, but I guess that's not the best approach?\n
      \n
      TLDR: I have -12v, 0v, +12v and +5v, what's the easiest way to get -5v?
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          +body: "thanks! gonna give it a try tomorrow. I'm pretty new to this, and never used opAmps in non-inverting configuration, so I missed this option"
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        +body: "Exiting! It has been some time for me too, let me know how you solved the problem at the end."
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      +body: """
        it worked! (at least in the sim)  \n
         thanks a lot!  \n
         I'm not sure I got all the math right, since I get 0 - 5.05V on the output, but it's not a deal breaker for me.  \n
         I attached the schematics, but not sure that images in comments federate from kbin to lemmy, so if you don't see it, try opening an original link to this comment.
        """
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    +body: "ah, a little bit of thinking helped me realize that I don't need 1k in inverting loop and then I'll get 5v instead of 5.05v :) and 100k can also be replaced by 1k"
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    So what should happen if you replace the 1k in the inverting loop by 0 Ohm is, you should get a 5V square wave.\n
    \n
    Is that correct?
    """
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      Hi! I'm working on an arduino project that has a -12v/0v/+12 psu. +12 is fed directly into arduinos voltage regulator, so there's also a +5v line available. I need to convert a -5v+5v signal to 0v+5v to feed it into arduinos analogue input and I've already mocked up a schematic in circuitjs based on an opamp that seems to do what I want. The only problem is that it needs -5v to shift the signal to be unipolar. I know that I can invert +5v using another opamp, but maybe there's some simpler way? I'd really like to avoid adding another opamp just for this? In this schematic I used simple voltage divider to get the needed voltage, but I guess that's not the best approach?\n
      \n
      TLDR: I have -12v, 0v, +12v and +5v, what's the easiest way to get -5v?
      """
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            +body: "Supply the OpAmp with +/-12V or +5/0V and use a non inverting Summing OpAmp Circuit to get your 0-5V signal. V1 is 5V, V2 your input."
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          +body: "thanks! gonna give it a try tomorrow. I'm pretty new to this, and never used opAmps in non-inverting configuration, so I missed this option"
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      +body: """
        it worked! (at least in the sim)  \n
         thanks a lot!  \n
         I'm not sure I got all the math right, since I get 0 - 5.05V on the output, but it's not a deal breaker for me.  \n
         I attached the schematics, but not sure that images in comments federate from kbin to lemmy, so if you don't see it, try opening an original link to this comment.
        """
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    +body: "ah, a little bit of thinking helped me realize that I don't need 1k in inverting loop and then I'll get 5v instead of 5.05v :) and 100k can also be replaced by 1k"
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    So what should happen if you replace the 1k in the inverting loop by 0 Ohm is, you should get a 5V square wave.\n
    \n
    Is that correct?
    """
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      Hi! I'm working on an arduino project that has a -12v/0v/+12 psu. +12 is fed directly into arduinos voltage regulator, so there's also a +5v line available. I need to convert a -5v+5v signal to 0v+5v to feed it into arduinos analogue input and I've already mocked up a schematic in circuitjs based on an opamp that seems to do what I want. The only problem is that it needs -5v to shift the signal to be unipolar. I know that I can invert +5v using another opamp, but maybe there's some simpler way? I'd really like to avoid adding another opamp just for this? In this schematic I used simple voltage divider to get the needed voltage, but I guess that's not the best approach?\n
      \n
      TLDR: I have -12v, 0v, +12v and +5v, what's the easiest way to get -5v?
      """
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              +body: "Supply the OpAmp with +/-12V or +5/0V and use a non inverting Summing OpAmp Circuit to get your 0-5V signal. V1 is 5V, V2 your input."
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            +body: "thanks! gonna give it a try tomorrow. I'm pretty new to this, and never used opAmps in non-inverting configuration, so I missed this option"
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          +body: "Exiting! It has been some time for me too, let me know how you solved the problem at the end."
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        +body: """
          it worked! (at least in the sim)  \n
           thanks a lot!  \n
           I'm not sure I got all the math right, since I get 0 - 5.05V on the output, but it's not a deal breaker for me.  \n
           I attached the schematics, but not sure that images in comments federate from kbin to lemmy, so if you don't see it, try opening an original link to this comment.
          """
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      +body: "ah, a little bit of thinking helped me realize that I don't need 1k in inverting loop and then I'll get 5v instead of 5.05v :) and 100k can also be replaced by 1k"
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      So what should happen if you replace the 1k in the inverting loop by 0 Ohm is, you should get a 5V square wave.\n
      \n
      Is that correct?
      """
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  +body: "No, with 0 Ohm I get a perfect 0+5v sine, just as I need. It's the other way round, it'll amplify the signal and clip off the top at about + supply voltage when you increase the resistance in the feedback loop, but it's not exactly square wave, as the bottom part of sine will remain intact. I use clipping schottky diodes to protect the arduino from voltage outside 0+5v range, this way if you increase input signal to say 20v peak to peak, you'll get more square-ish wave in 0+5v (I've attached the schematics)"
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      Hi! I'm working on an arduino project that has a -12v/0v/+12 psu. +12 is fed directly into arduinos voltage regulator, so there's also a +5v line available. I need to convert a -5v+5v signal to 0v+5v to feed it into arduinos analogue input and I've already mocked up a schematic in circuitjs based on an opamp that seems to do what I want. The only problem is that it needs -5v to shift the signal to be unipolar. I know that I can invert +5v using another opamp, but maybe there's some simpler way? I'd really like to avoid adding another opamp just for this? In this schematic I used simple voltage divider to get the needed voltage, but I guess that's not the best approach?\n
      \n
      TLDR: I have -12v, 0v, +12v and +5v, what's the easiest way to get -5v?
      """
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              +body: "Supply the OpAmp with +/-12V or +5/0V and use a non inverting Summing OpAmp Circuit to get your 0-5V signal. V1 is 5V, V2 your input."
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            +body: "thanks! gonna give it a try tomorrow. I'm pretty new to this, and never used opAmps in non-inverting configuration, so I missed this option"
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          +body: "Exiting! It has been some time for me too, let me know how you solved the problem at the end."
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        +body: """
          it worked! (at least in the sim)  \n
           thanks a lot!  \n
           I'm not sure I got all the math right, since I get 0 - 5.05V on the output, but it's not a deal breaker for me.  \n
           I attached the schematics, but not sure that images in comments federate from kbin to lemmy, so if you don't see it, try opening an original link to this comment.
          """
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      +body: "ah, a little bit of thinking helped me realize that I don't need 1k in inverting loop and then I'll get 5v instead of 5.05v :) and 100k can also be replaced by 1k"
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    +body: """
      So what should happen if you replace the 1k in the inverting loop by 0 Ohm is, you should get a 5V square wave.\n
      \n
      Is that correct?
      """
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  +body: "No, with 0 Ohm I get a perfect 0+5v sine, just as I need. It's the other way round, it'll amplify the signal and clip off the top at about + supply voltage when you increase the resistance in the feedback loop, but it's not exactly square wave, as the bottom part of sine will remain intact. I use clipping schottky diodes to protect the arduino from voltage outside 0+5v range, this way if you increase input signal to say 20v peak to peak, you'll get more square-ish wave in 0+5v (I've attached the schematics)"
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    +title: "What's a simplest way to get -5v from +/-12v?"
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      Hi! I'm working on an arduino project that has a -12v/0v/+12 psu. +12 is fed directly into arduinos voltage regulator, so there's also a +5v line available. I need to convert a -5v+5v signal to 0v+5v to feed it into arduinos analogue input and I've already mocked up a schematic in circuitjs based on an opamp that seems to do what I want. The only problem is that it needs -5v to shift the signal to be unipolar. I know that I can invert +5v using another opamp, but maybe there's some simpler way? I'd really like to avoid adding another opamp just for this? In this schematic I used simple voltage divider to get the needed voltage, but I guess that's not the best approach?\n
      \n
      TLDR: I have -12v, 0v, +12v and +5v, what's the easiest way to get -5v?
      """
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              +body: "Supply the OpAmp with +/-12V or +5/0V and use a non inverting Summing OpAmp Circuit to get your 0-5V signal. V1 is 5V, V2 your input."
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            +body: "thanks! gonna give it a try tomorrow. I'm pretty new to this, and never used opAmps in non-inverting configuration, so I missed this option"
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          +body: "Exiting! It has been some time for me too, let me know how you solved the problem at the end."
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        +body: """
          it worked! (at least in the sim)  \n
           thanks a lot!  \n
           I'm not sure I got all the math right, since I get 0 - 5.05V on the output, but it's not a deal breaker for me.  \n
           I attached the schematics, but not sure that images in comments federate from kbin to lemmy, so if you don't see it, try opening an original link to this comment.
          """
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      +body: "ah, a little bit of thinking helped me realize that I don't need 1k in inverting loop and then I'll get 5v instead of 5.05v :) and 100k can also be replaced by 1k"
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    +body: """
      So what should happen if you replace the 1k in the inverting loop by 0 Ohm is, you should get a 5V square wave.\n
      \n
      Is that correct?
      """
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  +body: "No, with 0 Ohm I get a perfect 0+5v sine, just as I need. It's the other way round, it'll amplify the signal and clip off the top at about + supply voltage when you increase the resistance in the feedback loop, but it's not exactly square wave, as the bottom part of sine will remain intact. I use clipping schottky diodes to protect the arduino from voltage outside 0+5v range, this way if you increase input signal to say 20v peak to peak, you'll get more square-ish wave in 0+5v (I've attached the schematics)"
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      Hi! I'm working on an arduino project that has a -12v/0v/+12 psu. +12 is fed directly into arduinos voltage regulator, so there's also a +5v line available. I need to convert a -5v+5v signal to 0v+5v to feed it into arduinos analogue input and I've already mocked up a schematic in circuitjs based on an opamp that seems to do what I want. The only problem is that it needs -5v to shift the signal to be unipolar. I know that I can invert +5v using another opamp, but maybe there's some simpler way? I'd really like to avoid adding another opamp just for this? In this schematic I used simple voltage divider to get the needed voltage, but I guess that's not the best approach?\n
      \n
      TLDR: I have -12v, 0v, +12v and +5v, what's the easiest way to get -5v?
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                +body: "Supply the OpAmp with +/-12V or +5/0V and use a non inverting Summing OpAmp Circuit to get your 0-5V signal. V1 is 5V, V2 your input."
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              +body: "thanks! gonna give it a try tomorrow. I'm pretty new to this, and never used opAmps in non-inverting configuration, so I missed this option"
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            +body: "Exiting! It has been some time for me too, let me know how you solved the problem at the end."
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          +body: """
            it worked! (at least in the sim)  \n
             thanks a lot!  \n
             I'm not sure I got all the math right, since I get 0 - 5.05V on the output, but it's not a deal breaker for me.  \n
             I attached the schematics, but not sure that images in comments federate from kbin to lemmy, so if you don't see it, try opening an original link to this comment.
            """
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        +body: "ah, a little bit of thinking helped me realize that I don't need 1k in inverting loop and then I'll get 5v instead of 5.05v :) and 100k can also be replaced by 1k"
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      +body: """
        So what should happen if you replace the 1k in the inverting loop by 0 Ohm is, you should get a 5V square wave.\n
        \n
        Is that correct?
        """
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    +body: "No, with 0 Ohm I get a perfect 0+5v sine, just as I need. It's the other way round, it'll amplify the signal and clip off the top at about + supply voltage when you increase the resistance in the feedback loop, but it's not exactly square wave, as the bottom part of sine will remain intact. I use clipping schottky diodes to protect the arduino from voltage outside 0+5v range, this way if you increase input signal to say 20v peak to peak, you'll get more square-ish wave in 0+5v (I've attached the schematics)"
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  +body: """
    You’re right of course. Two more questions if you don’t mind:\n
    \n
    - 1. what’s the 1k || 100k doing?\n
    - 2. if you don’t want more than 5V at the output of the OpAmp, wouldn’t it be easier to just supply the OpAmp with 5V instead of adding a shottky diode which has a forward voltage of around 0.6V? As I understand the screenshot the voltage is 5.4V at that exact point and it could theoretically raise to 5.6V.\n
    \n
    At the moment you’re also mixing up your + input. 10V AC + 5V DC result in 7.5V input in your sim.
    """
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      Hi! I'm working on an arduino project that has a -12v/0v/+12 psu. +12 is fed directly into arduinos voltage regulator, so there's also a +5v line available. I need to convert a -5v+5v signal to 0v+5v to feed it into arduinos analogue input and I've already mocked up a schematic in circuitjs based on an opamp that seems to do what I want. The only problem is that it needs -5v to shift the signal to be unipolar. I know that I can invert +5v using another opamp, but maybe there's some simpler way? I'd really like to avoid adding another opamp just for this? In this schematic I used simple voltage divider to get the needed voltage, but I guess that's not the best approach?\n
      \n
      TLDR: I have -12v, 0v, +12v and +5v, what's the easiest way to get -5v?
      """
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                +body: "Supply the OpAmp with +/-12V or +5/0V and use a non inverting Summing OpAmp Circuit to get your 0-5V signal. V1 is 5V, V2 your input."
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              +body: "thanks! gonna give it a try tomorrow. I'm pretty new to this, and never used opAmps in non-inverting configuration, so I missed this option"
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            +body: "Exiting! It has been some time for me too, let me know how you solved the problem at the end."
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          +body: """
            it worked! (at least in the sim)  \n
             thanks a lot!  \n
             I'm not sure I got all the math right, since I get 0 - 5.05V on the output, but it's not a deal breaker for me.  \n
             I attached the schematics, but not sure that images in comments federate from kbin to lemmy, so if you don't see it, try opening an original link to this comment.
            """
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        +body: "ah, a little bit of thinking helped me realize that I don't need 1k in inverting loop and then I'll get 5v instead of 5.05v :) and 100k can also be replaced by 1k"
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      +body: """
        So what should happen if you replace the 1k in the inverting loop by 0 Ohm is, you should get a 5V square wave.\n
        \n
        Is that correct?
        """
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    +body: "No, with 0 Ohm I get a perfect 0+5v sine, just as I need. It's the other way round, it'll amplify the signal and clip off the top at about + supply voltage when you increase the resistance in the feedback loop, but it's not exactly square wave, as the bottom part of sine will remain intact. I use clipping schottky diodes to protect the arduino from voltage outside 0+5v range, this way if you increase input signal to say 20v peak to peak, you'll get more square-ish wave in 0+5v (I've attached the schematics)"
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  +body: """
    You’re right of course. Two more questions if you don’t mind:\n
    \n
    - 1. what’s the 1k || 100k doing?\n
    - 2. if you don’t want more than 5V at the output of the OpAmp, wouldn’t it be easier to just supply the OpAmp with 5V instead of adding a shottky diode which has a forward voltage of around 0.6V? As I understand the screenshot the voltage is 5.4V at that exact point and it could theoretically raise to 5.6V.\n
    \n
    At the moment you’re also mixing up your + input. 10V AC + 5V DC result in 7.5V input in your sim.
    """
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      Hi! I'm working on an arduino project that has a -12v/0v/+12 psu. +12 is fed directly into arduinos voltage regulator, so there's also a +5v line available. I need to convert a -5v+5v signal to 0v+5v to feed it into arduinos analogue input and I've already mocked up a schematic in circuitjs based on an opamp that seems to do what I want. The only problem is that it needs -5v to shift the signal to be unipolar. I know that I can invert +5v using another opamp, but maybe there's some simpler way? I'd really like to avoid adding another opamp just for this? In this schematic I used simple voltage divider to get the needed voltage, but I guess that's not the best approach?\n
      \n
      TLDR: I have -12v, 0v, +12v and +5v, what's the easiest way to get -5v?
      """
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                +body: "Supply the OpAmp with +/-12V or +5/0V and use a non inverting Summing OpAmp Circuit to get your 0-5V signal. V1 is 5V, V2 your input."
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              +body: "thanks! gonna give it a try tomorrow. I'm pretty new to this, and never used opAmps in non-inverting configuration, so I missed this option"
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            +body: "Exiting! It has been some time for me too, let me know how you solved the problem at the end."
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          +body: """
            it worked! (at least in the sim)  \n
             thanks a lot!  \n
             I'm not sure I got all the math right, since I get 0 - 5.05V on the output, but it's not a deal breaker for me.  \n
             I attached the schematics, but not sure that images in comments federate from kbin to lemmy, so if you don't see it, try opening an original link to this comment.
            """
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        +body: "ah, a little bit of thinking helped me realize that I don't need 1k in inverting loop and then I'll get 5v instead of 5.05v :) and 100k can also be replaced by 1k"
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      +body: """
        So what should happen if you replace the 1k in the inverting loop by 0 Ohm is, you should get a 5V square wave.\n
        \n
        Is that correct?
        """
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    +body: "No, with 0 Ohm I get a perfect 0+5v sine, just as I need. It's the other way round, it'll amplify the signal and clip off the top at about + supply voltage when you increase the resistance in the feedback loop, but it's not exactly square wave, as the bottom part of sine will remain intact. I use clipping schottky diodes to protect the arduino from voltage outside 0+5v range, this way if you increase input signal to say 20v peak to peak, you'll get more square-ish wave in 0+5v (I've attached the schematics)"
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  +body: """
    You’re right of course. Two more questions if you don’t mind:\n
    \n
    - 1. what’s the 1k || 100k doing?\n
    - 2. if you don’t want more than 5V at the output of the OpAmp, wouldn’t it be easier to just supply the OpAmp with 5V instead of adding a shottky diode which has a forward voltage of around 0.6V? As I understand the screenshot the voltage is 5.4V at that exact point and it could theoretically raise to 5.6V.\n
    \n
    At the moment you’re also mixing up your + input. 10V AC + 5V DC result in 7.5V input in your sim.
    """
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      Hi! I'm working on an arduino project that has a -12v/0v/+12 psu. +12 is fed directly into arduinos voltage regulator, so there's also a +5v line available. I need to convert a -5v+5v signal to 0v+5v to feed it into arduinos analogue input and I've already mocked up a schematic in circuitjs based on an opamp that seems to do what I want. The only problem is that it needs -5v to shift the signal to be unipolar. I know that I can invert +5v using another opamp, but maybe there's some simpler way? I'd really like to avoid adding another opamp just for this? In this schematic I used simple voltage divider to get the needed voltage, but I guess that's not the best approach?\n
      \n
      TLDR: I have -12v, 0v, +12v and +5v, what's the easiest way to get -5v?
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                  +body: "Supply the OpAmp with +/-12V or +5/0V and use a non inverting Summing OpAmp Circuit to get your 0-5V signal. V1 is 5V, V2 your input."
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                +body: "thanks! gonna give it a try tomorrow. I'm pretty new to this, and never used opAmps in non-inverting configuration, so I missed this option"
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              +body: "Exiting! It has been some time for me too, let me know how you solved the problem at the end."
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            +body: """
              it worked! (at least in the sim)  \n
               thanks a lot!  \n
               I'm not sure I got all the math right, since I get 0 - 5.05V on the output, but it's not a deal breaker for me.  \n
               I attached the schematics, but not sure that images in comments federate from kbin to lemmy, so if you don't see it, try opening an original link to this comment.
              """
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          +body: "ah, a little bit of thinking helped me realize that I don't need 1k in inverting loop and then I'll get 5v instead of 5.05v :) and 100k can also be replaced by 1k"
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        +body: """
          So what should happen if you replace the 1k in the inverting loop by 0 Ohm is, you should get a 5V square wave.\n
          \n
          Is that correct?
          """
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      +body: "No, with 0 Ohm I get a perfect 0+5v sine, just as I need. It's the other way round, it'll amplify the signal and clip off the top at about + supply voltage when you increase the resistance in the feedback loop, but it's not exactly square wave, as the bottom part of sine will remain intact. I use clipping schottky diodes to protect the arduino from voltage outside 0+5v range, this way if you increase input signal to say 20v peak to peak, you'll get more square-ish wave in 0+5v (I've attached the schematics)"
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    +body: """
      You’re right of course. Two more questions if you don’t mind:\n
      \n
      - 1. what’s the 1k || 100k doing?\n
      - 2. if you don’t want more than 5V at the output of the OpAmp, wouldn’t it be easier to just supply the OpAmp with 5V instead of adding a shottky diode which has a forward voltage of around 0.6V? As I understand the screenshot the voltage is 5.4V at that exact point and it could theoretically raise to 5.6V.\n
      \n
      At the moment you’re also mixing up your + input. 10V AC + 5V DC result in 7.5V input in your sim.
      """
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  +body: """
    1. it does nothing 😅 I just forgot to remove it from the sim\n
    2. you mean like power it with 0+5v? I think it won't work with negative input voltages then, right? and I'm using tl074 and I'm not sure that 0+5v is enough juice for it, and I use remaining 3 opamps for other stuff, so it's not really an option for me. the sim didn't have shottky diodes, so this measurements are not 100% accurate, but I used this approach to protect arduino inputs in another project, and it worked well. And yeah, I cranked up the input signal to +/-10v just to check the clipping, it'll normally stay within +/-5v\n
    \n
    I already ordered PCB for the prototype. I hope it'll work fine. Thanks a lot for your help :)
    """
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    +slug: "What-s-a-simplest-way-to-get-5v-from-12v"
    +title: "What's a simplest way to get -5v from +/-12v?"
    +url: null
    +body: """
      Hi! I'm working on an arduino project that has a -12v/0v/+12 psu. +12 is fed directly into arduinos voltage regulator, so there's also a +5v line available. I need to convert a -5v+5v signal to 0v+5v to feed it into arduinos analogue input and I've already mocked up a schematic in circuitjs based on an opamp that seems to do what I want. The only problem is that it needs -5v to shift the signal to be unipolar. I know that I can invert +5v using another opamp, but maybe there's some simpler way? I'd really like to avoid adding another opamp just for this? In this schematic I used simple voltage divider to get the needed voltage, but I guess that's not the best approach?\n
      \n
      TLDR: I have -12v, 0v, +12v and +5v, what's the easiest way to get -5v?
      """
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                  +body: "Supply the OpAmp with +/-12V or +5/0V and use a non inverting Summing OpAmp Circuit to get your 0-5V signal. V1 is 5V, V2 your input."
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                +body: "thanks! gonna give it a try tomorrow. I'm pretty new to this, and never used opAmps in non-inverting configuration, so I missed this option"
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              +body: "Exiting! It has been some time for me too, let me know how you solved the problem at the end."
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            +body: """
              it worked! (at least in the sim)  \n
               thanks a lot!  \n
               I'm not sure I got all the math right, since I get 0 - 5.05V on the output, but it's not a deal breaker for me.  \n
               I attached the schematics, but not sure that images in comments federate from kbin to lemmy, so if you don't see it, try opening an original link to this comment.
              """
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          +body: "ah, a little bit of thinking helped me realize that I don't need 1k in inverting loop and then I'll get 5v instead of 5.05v :) and 100k can also be replaced by 1k"
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          -bodyTs: "'100k':30 '1k':15,36 '5.05':27 '5v':24 'ah':1 'also':32 'bit':4 'get':23 'help':7 'instead':25 'invert':17 'littl':3 'll':22 'loop':18 'need':14 'realiz':9 'replac':34 'think':6 'v':28"
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        +body: """
          So what should happen if you replace the 1k in the inverting loop by 0 Ohm is, you should get a 5V square wave.\n
          \n
          Is that correct?
          """
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      +body: "No, with 0 Ohm I get a perfect 0+5v sine, just as I need. It's the other way round, it'll amplify the signal and clip off the top at about + supply voltage when you increase the resistance in the feedback loop, but it's not exactly square wave, as the bottom part of sine will remain intact. I use clipping schottky diodes to protect the arduino from voltage outside 0+5v range, this way if you increase input signal to say 20v peak to peak, you'll get more square-ish wave in 0+5v (I've attached the schematics)"
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    +body: """
      You’re right of course. Two more questions if you don’t mind:\n
      \n
      - 1. what’s the 1k || 100k doing?\n
      - 2. if you don’t want more than 5V at the output of the OpAmp, wouldn’t it be easier to just supply the OpAmp with 5V instead of adding a shottky diode which has a forward voltage of around 0.6V? As I understand the screenshot the voltage is 5.4V at that exact point and it could theoretically raise to 5.6V.\n
      \n
      At the moment you’re also mixing up your + input. 10V AC + 5V DC result in 7.5V input in your sim.
      """
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  +body: """
    1. it does nothing 😅 I just forgot to remove it from the sim\n
    2. you mean like power it with 0+5v? I think it won't work with negative input voltages then, right? and I'm using tl074 and I'm not sure that 0+5v is enough juice for it, and I use remaining 3 opamps for other stuff, so it's not really an option for me. the sim didn't have shottky diodes, so this measurements are not 100% accurate, but I used this approach to protect arduino inputs in another project, and it worked well. And yeah, I cranked up the input signal to +/-10v just to check the clipping, it'll normally stay within +/-5v\n
    \n
    I already ordered PCB for the prototype. I hope it'll work fine. Thanks a lot for your help :)
    """
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    +slug: "What-s-a-simplest-way-to-get-5v-from-12v"
    +title: "What's a simplest way to get -5v from +/-12v?"
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    +body: """
      Hi! I'm working on an arduino project that has a -12v/0v/+12 psu. +12 is fed directly into arduinos voltage regulator, so there's also a +5v line available. I need to convert a -5v+5v signal to 0v+5v to feed it into arduinos analogue input and I've already mocked up a schematic in circuitjs based on an opamp that seems to do what I want. The only problem is that it needs -5v to shift the signal to be unipolar. I know that I can invert +5v using another opamp, but maybe there's some simpler way? I'd really like to avoid adding another opamp just for this? In this schematic I used simple voltage divider to get the needed voltage, but I guess that's not the best approach?\n
      \n
      TLDR: I have -12v, 0v, +12v and +5v, what's the easiest way to get -5v?
      """
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                  +body: "Supply the OpAmp with +/-12V or +5/0V and use a non inverting Summing OpAmp Circuit to get your 0-5V signal. V1 is 5V, V2 your input."
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                +body: "thanks! gonna give it a try tomorrow. I'm pretty new to this, and never used opAmps in non-inverting configuration, so I missed this option"
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              +body: "Exiting! It has been some time for me too, let me know how you solved the problem at the end."
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            +body: """
              it worked! (at least in the sim)  \n
               thanks a lot!  \n
               I'm not sure I got all the math right, since I get 0 - 5.05V on the output, but it's not a deal breaker for me.  \n
               I attached the schematics, but not sure that images in comments federate from kbin to lemmy, so if you don't see it, try opening an original link to this comment.
              """
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          +body: "ah, a little bit of thinking helped me realize that I don't need 1k in inverting loop and then I'll get 5v instead of 5.05v :) and 100k can also be replaced by 1k"
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        +body: """
          So what should happen if you replace the 1k in the inverting loop by 0 Ohm is, you should get a 5V square wave.\n
          \n
          Is that correct?
          """
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      +body: "No, with 0 Ohm I get a perfect 0+5v sine, just as I need. It's the other way round, it'll amplify the signal and clip off the top at about + supply voltage when you increase the resistance in the feedback loop, but it's not exactly square wave, as the bottom part of sine will remain intact. I use clipping schottky diodes to protect the arduino from voltage outside 0+5v range, this way if you increase input signal to say 20v peak to peak, you'll get more square-ish wave in 0+5v (I've attached the schematics)"
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    +body: """
      You’re right of course. Two more questions if you don’t mind:\n
      \n
      - 1. what’s the 1k || 100k doing?\n
      - 2. if you don’t want more than 5V at the output of the OpAmp, wouldn’t it be easier to just supply the OpAmp with 5V instead of adding a shottky diode which has a forward voltage of around 0.6V? As I understand the screenshot the voltage is 5.4V at that exact point and it could theoretically raise to 5.6V.\n
      \n
      At the moment you’re also mixing up your + input. 10V AC + 5V DC result in 7.5V input in your sim.
      """
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  +body: """
    1. it does nothing 😅 I just forgot to remove it from the sim\n
    2. you mean like power it with 0+5v? I think it won't work with negative input voltages then, right? and I'm using tl074 and I'm not sure that 0+5v is enough juice for it, and I use remaining 3 opamps for other stuff, so it's not really an option for me. the sim didn't have shottky diodes, so this measurements are not 100% accurate, but I used this approach to protect arduino inputs in another project, and it worked well. And yeah, I cranked up the input signal to +/-10v just to check the clipping, it'll normally stay within +/-5v\n
    \n
    I already ordered PCB for the prototype. I hope it'll work fine. Thanks a lot for your help :)
    """
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"Scheb\TwoFactorBundle\Security\Authorization\Voter\TwoFactorInProgressVoter"
ACCESS ABSTAIN
"App\Security\Voter\EntryCommentVoter"
ACCESS DENIED
"App\Security\Voter\EntryVoter"
ACCESS ABSTAIN
"App\Security\Voter\MagazineVoter"
ACCESS ABSTAIN
"App\Security\Voter\MessageThreadVoter"
ACCESS ABSTAIN
"App\Security\Voter\MessageVoter"
ACCESS ABSTAIN
"App\Security\Voter\NotificationVoter"
ACCESS ABSTAIN
"App\Security\Voter\OAuth2UserConsentVoter"
ACCESS ABSTAIN
"App\Security\Voter\PostCommentVoter"
ACCESS ABSTAIN
"App\Security\Voter\PostVoter"
ACCESS ABSTAIN
"App\Security\Voter\UserVoter"
ACCESS ABSTAIN
Show voter details
45 DENIED edit
App\Entity\Magazine {#265
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    **For questions about component-level electronic circuits, tools and equipment.**\n
    \n
    Rules\n
    -----\n
    \n
    1: Be nice.\n
    \n
    2: Be on-topic (eg: *Electronic*, not *electrical*).\n
    \n
    3: No commercial stuff, buying, selling or valuations.\n
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    ---
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ACCESS ABSTAIN
"App\Security\Voter\EntryCommentVoter"
ACCESS ABSTAIN
"App\Security\Voter\EntryVoter"
ACCESS ABSTAIN
"App\Security\Voter\MagazineVoter"
ACCESS DENIED
"App\Security\Voter\MessageThreadVoter"
ACCESS ABSTAIN
"App\Security\Voter\MessageVoter"
ACCESS ABSTAIN
"App\Security\Voter\NotificationVoter"
ACCESS ABSTAIN
"App\Security\Voter\OAuth2UserConsentVoter"
ACCESS ABSTAIN
"App\Security\Voter\PostCommentVoter"
ACCESS ABSTAIN
"App\Security\Voter\PostVoter"
ACCESS ABSTAIN
"App\Security\Voter\UserVoter"
ACCESS ABSTAIN
Show voter details