MBM, 10 months ago That’s if you add two of the same odd number. The more general proof is basically the same though: let n and m be integers, then 2n+1 and 2m+1 are odd. (2n+1) + (2m+1) = 2n + 2m + 2 = 2(n+m+1) which will be even.
That’s if you add two of the same odd number. The more general proof is basically the same though: let n and m be integers, then 2n+1 and 2m+1 are odd. (2n+1) + (2m+1) = 2n + 2m + 2 = 2(n+m+1) which will be even.
n
m
2n+1
2m+1
(2n+1) + (2m+1) = 2n + 2m + 2 = 2(n+m+1)