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jjagaimo, (edited ) to askelectronics in Strange board behavior when switching power supplies

Look for differences and bad joints

  • C4 looks not connected right, maybe c10 and c14
  • C16 missing
  • Solder joint messy up above C17
  • The two through hole pads by C19/20 arent soldered and the one above it looks to be a bad joint
  • jumpers on the right arent connected in the same spot
  • extra traces by the IC
  • components can die, especially ICs and capacitors from ESD and drops respectively
  • PCBs themselves can sometimes just be faulty from the factory and have damaged traces.

Another thing is that small ICs like that tend to be fairly difficult to stick down all the pads. Reworking that might be a good option if checking the above doesnt work

jjagaimo, to news in Video of Palestinians stripped, forced to sit outside by IDF soldiers raises ire

Bootlicker

jjagaimo, to askelectronics in How to improve my battery measurement circuit?

It is an N channel FET. The concept is called “bootstrapping” since Vgs needs to be greater than Vth for the MOSFET to be on. When the FET is on the high side and you want the full 9V on the output, you use the diode to charge the capacitor, and the other side of the cap is 0V. Then, when the other side of the cap is connected to 9V, the charge on the cap can’t go anywhere so the voltage on the other side jumps to 18V. This creates a Vgs of 9V. Ideally you would have something better to drive the gate to fully turn off the FET, but I just used a quick and dirty driver where the bootstrap capacitor directly feeds the gate instead of being the input to the driver. Because if this, the Vgs doesn’t drop completely to 0

jjagaimo, to askelectronics in How to improve my battery measurement circuit?

You could use a single MOSFET on the high side of the divider and use a cap + diode to boost the voltage and fully turn on the FET:

https://lemmy.ca/pictrs/image/8b22113e-3ad3-40c1-80ee-e7b3e6be24cb.png

My gate driver is fairly crude but you could probably make something a bit better with a PNP transistor and either pull it down or leave it floating, or instead use a szaiklai pair

jjagaimo, to electronics in Noob question regarding JDS2915 signal generator

Signal generators have an internal impedance of 50 ohms and expect a load of 50 ohms when the 50 ohm setting is selected. The 50 ohm impedance prevents reflections of high frequency (rf) signals as it changes mediums. Ideally you should not be using a signal generator to drive an output, but instead buffer it or use an amplifier. If you use high-z the output voltage is exactly what you set it to (e.g. 5Vpp) but with the 50 ohm setting the applies voltage is twice that with an internal resistance of 50 ohms.

jjagaimo, to lemmyshitpost in That number again is 1-800-O-Y-S-T-E-R. CALL NOW!

Femur breaker

jjagaimo, to asklemmy in Where do you get affordable scented candles?

To fix tunnelled candles, maybe try wrapping them in foil to help heat the outer edges and level them out

jjagaimo, to askelectronics in Strange board behavior when switching power supplies

traces by the IC

I was referring to it more as a difference which might be the source of the issue. For example, one via is fairly close to the pad for C16 which could be shorted (probably isn’t, but still a good idea to check). It could be a wiring issue but could also be a board manufacture issue.

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