jjagaimo

@jjagaimo@lemmy.ca

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jjagaimo,

Browse> extensions>tap shield>trust

worked for me

jjagaimo,

Rn it’s just reskinned tachiyomi so export backup > import backup in mihon

jjagaimo,

Femur breaker

jjagaimo,

while(1){ suffer(); }

jjagaimo,

It really depends how much power/current you are switching. If you are switching 1A with a beefy heatsink FET, the time spent in the linear region is short enough it shouldn’t be a problem. If you are switching 50A though it then you might have a problem. Depending on how that gate divider is set up, you could still potentially damage the gate of the FET when shorting it to ground to discharge it if I understand how its hooked up correctly.

Ideally you would use some kind of FET driver with a voltage source (e.g. linear regulator) to turn on and off the gate plus the gate resistor.

jjagaimo,

He’s a former pig himself

ACAB

jjagaimo,

Bootlicker

jjagaimo,

We here for a good time, not a long time 😤

jjagaimo, (edited )

Afaik this is just fear mongering

That article cites no sources, and the FDA has retracted requiring warnings for products containing olestra

According to Wikipedia:

When removing the olestra warning label, the FDA cited a six-week P&G study of more than 3000 people showing the olestra-eating group experienced only a small increase in bowel movement frequency compared to the control group.The FDA concluded that “subjects eating olestra-containing chips were no more likely to report having had loose stools, abdominal cramps, or any other GI symptom compared to subjects eating an equivalent amount of [potato] chips”

Source

Where I originally heard about olestra

jjagaimo,

Something everyone here seems to be forgetting is that even if you are getting the same amount of sleep, sleeping at a time which fits your biological clock better is better for you. I can get some amount of sleep and wake up at 5am and be tired the whole day, and yet if I wake up at 8-9am with the same amount of sleep I am perfectly functional the whole day.

jjagaimo,

School had me at 1, 2 & 3. Work has me at 4.

jjagaimo,

I prefer to pirate adults

jjagaimo,

To fix tunnelled candles, maybe try wrapping them in foil to help heat the outer edges and level them out

jjagaimo, (edited )

I thought theory was a fire/smoke leaking /explosion inside the tent caused by the homemade stove leading to them cutting their way out and running, and then getting separated and lost in the confusion, before succumbing to hypothermia

jjagaimo,

Mom would be sad

jjagaimo,

How has he looked inside my brain and extracted its essence

jjagaimo,

Considering it was one of the basic labs I did in college physics that pretty much every student has to take, and a significant portion of the classes just do the experiments wrong until they get helped, there’s probably just enough familiarity to kinda know what’s happening but with major misconceptions.

jjagaimo,

You could use a single MOSFET on the high side of the divider and use a cap + diode to boost the voltage and fully turn on the FET:

https://lemmy.ca/pictrs/image/8b22113e-3ad3-40c1-80ee-e7b3e6be24cb.png

My gate driver is fairly crude but you could probably make something a bit better with a PNP transistor and either pull it down or leave it floating, or instead use a szaiklai pair

jjagaimo,

It is an N channel FET. The concept is called “bootstrapping” since Vgs needs to be greater than Vth for the MOSFET to be on. When the FET is on the high side and you want the full 9V on the output, you use the diode to charge the capacitor, and the other side of the cap is 0V. Then, when the other side of the cap is connected to 9V, the charge on the cap can’t go anywhere so the voltage on the other side jumps to 18V. This creates a Vgs of 9V. Ideally you would have something better to drive the gate to fully turn off the FET, but I just used a quick and dirty driver where the bootstrap capacitor directly feeds the gate instead of being the input to the driver. Because if this, the Vgs doesn’t drop completely to 0

jjagaimo,

Signal generators have an internal impedance of 50 ohms and expect a load of 50 ohms when the 50 ohm setting is selected. The 50 ohm impedance prevents reflections of high frequency (rf) signals as it changes mediums. Ideally you should not be using a signal generator to drive an output, but instead buffer it or use an amplifier. If you use high-z the output voltage is exactly what you set it to (e.g. 5Vpp) but with the 50 ohm setting the applies voltage is twice that with an internal resistance of 50 ohms.

jjagaimo,

traces by the IC

I was referring to it more as a difference which might be the source of the issue. For example, one via is fairly close to the pad for C16 which could be shorted (probably isn’t, but still a good idea to check). It could be a wiring issue but could also be a board manufacture issue.

jjagaimo, (edited )

Look for differences and bad joints

  • C4 looks not connected right, maybe c10 and c14
  • C16 missing
  • Solder joint messy up above C17
  • The two through hole pads by C19/20 arent soldered and the one above it looks to be a bad joint
  • jumpers on the right arent connected in the same spot
  • extra traces by the IC
  • components can die, especially ICs and capacitors from ESD and drops respectively
  • PCBs themselves can sometimes just be faulty from the factory and have damaged traces.

Another thing is that small ICs like that tend to be fairly difficult to stick down all the pads. Reworking that might be a good option if checking the above doesnt work

What creates resistance in a circuit?

I'm planning to add a momentary switch to a single loop DC circuit. Will this cause any amount of resistance in the circuit? I'm a complete noobie when it comes to electronics, any resource links or clarification is appreciated. I know the type of material/width of wire and a pot will cause resistance but will any component put...

jjagaimo,

Every material has resistance.

You can calculate a materials resistance using its resistivity and dimensions. For a simple wire, the formula is R = p*l/A, where p is resistivity, l is length, and A is area (cross sectional. Imagine cutting the wire, you'd see a circular cross section).

Some materials like copper have very low resistance.

Some materials like oil have a very high resistance.

Some materials like carbon have a resistance somewhere in between, but generally fairly high.

Resistors use a strip of carbon to make a high resistance path.

Resistance in a switch is typically minimized by design, so introducing a switch or button should not introduce a lot of resistance. It is tyically better not to use switches of this type in signal critical or high power applications (e.g. sound or battery charging), but charging up a small capacitor or powering a small dc circuit should be fine

To measure resistance, one can use a multimeter. This makes use of Ohm's law. Ohms law shows that

V=I*R

Where V is voltage, R is resistance, and I is current. When a small voltage is applied across your component, the current is measured. Then using the current and voltage, it can figure out what the resistance is. It shows it to you on a display so all you have to do is touch the probe tips to the two legs of the switch.

For a switch this will typically be less than 1 ohm. If you buy from a reputable distributor (e.g. digikey, mouser, arrow, farnell, even LCSC) you can get the "datasheet" and look for the constact resistance. This might be a bit harder with ebay/amazon/aliexpress parts, so just stick with a multimeter.

A cheap handheld one is fine, but I'd say prob look for an EEVBlog or other video looking at good cheap meters; you can get pretty good stuff without breaking the bank. Don't stress over it though; any multimeter is better than no multimeter

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